-3.6x+360=0.05x^2+0.6x+4

Solution for -3.6x+360=0.05x^2+0.6x+4 equation:

-3.6x+360=0.05x^2+0.6x+4

We move all terms to the left:

-3.6x+360-(0.05x^2+0.6x+4)=0

We get rid of parentheses

-0.05x^2-3.6x-0.6x-4+360=0

We add all the numbers together, and all the variables

-0.05x^2-4.2x+356=0

a = -0.05; b = -4.2; c = +356;
Δ = b2-4ac
Δ = -4.22-4·(-0.05)·356
Δ = 88.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.2)-\sqrt{88.84}}{2*-0.05}=\frac{4.2-\sqrt{88.84}}{-0.1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.2)+\sqrt{88.84}}{2*-0.05}=\frac{4.2+\sqrt{88.84}}{-0.1}
$